Integrand size = 21, antiderivative size = 59 \[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\frac {x \sqrt [3]{a+b x^3} \operatorname {AppellF1}\left (\frac {1}{3},-\frac {1}{3},3,\frac {4}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{c^3 \sqrt [3]{1+\frac {b x^3}{a}}} \]
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Time = 0.02 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {441, 440} \[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\frac {x \sqrt [3]{a+b x^3} \operatorname {AppellF1}\left (\frac {1}{3},-\frac {1}{3},3,\frac {4}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{c^3 \sqrt [3]{\frac {b x^3}{a}+1}} \]
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Rule 440
Rule 441
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt [3]{a+b x^3} \int \frac {\sqrt [3]{1+\frac {b x^3}{a}}}{\left (c+d x^3\right )^3} \, dx}{\sqrt [3]{1+\frac {b x^3}{a}}} \\ & = \frac {x \sqrt [3]{a+b x^3} F_1\left (\frac {1}{3};-\frac {1}{3},3;\frac {4}{3};-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{c^3 \sqrt [3]{1+\frac {b x^3}{a}}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(407\) vs. \(2(59)=118\).
Time = 10.62 (sec) , antiderivative size = 407, normalized size of antiderivative = 6.90 \[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\frac {-b (-4 b c+5 a d) x^4 \left (1+\frac {b x^3}{a}\right )^{2/3} \operatorname {AppellF1}\left (\frac {4}{3},\frac {2}{3},1,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )+\frac {c \left (16 a c x \left (-b^2 c x^3 \left (7 c+4 d x^3\right )+3 a^2 d \left (6 c+5 d x^3\right )+a b \left (-18 c^2-7 c d x^3+5 d^2 x^6\right )\right ) \operatorname {AppellF1}\left (\frac {1}{3},\frac {2}{3},1,\frac {4}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )-4 x^4 \left (a+b x^3\right ) \left (-b c \left (7 c+4 d x^3\right )+a d \left (8 c+5 d x^3\right )\right ) \left (3 a d \operatorname {AppellF1}\left (\frac {4}{3},\frac {2}{3},2,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )+2 b c \operatorname {AppellF1}\left (\frac {4}{3},\frac {5}{3},1,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )\right )\right )}{\left (c+d x^3\right )^2 \left (-4 a c \operatorname {AppellF1}\left (\frac {1}{3},\frac {2}{3},1,\frac {4}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )+x^3 \left (3 a d \operatorname {AppellF1}\left (\frac {4}{3},\frac {2}{3},2,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )+2 b c \operatorname {AppellF1}\left (\frac {4}{3},\frac {5}{3},1,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )\right )\right )}}{72 c^3 (b c-a d) \left (a+b x^3\right )^{2/3}} \]
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\[\int \frac {\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{\left (d \,x^{3}+c \right )^{3}}d x\]
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Timed out. \[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\text {Timed out} \]
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\[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\int \frac {\sqrt [3]{a + b x^{3}}}{\left (c + d x^{3}\right )^{3}}\, dx \]
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\[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {1}{3}}}{{\left (d x^{3} + c\right )}^{3}} \,d x } \]
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\[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {1}{3}}}{{\left (d x^{3} + c\right )}^{3}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt [3]{a+b x^3}}{\left (c+d x^3\right )^3} \, dx=\int \frac {{\left (b\,x^3+a\right )}^{1/3}}{{\left (d\,x^3+c\right )}^3} \,d x \]
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